Can You Prove Gy^3+(y-G)^3 Equals Zero Given x^2+x+G=0?

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SUMMARY

The discussion centers on proving the equation Gy^3 + (y - G)^3 = 0 under the condition x^2 + x + G = 0, with y defined as y = x + 1/x. The participants analyze the expressions Gy^3 and (y - G)^3, concluding that they are not equal based on their calculations. The confusion arises regarding the correct interpretation of y, with a specific focus on whether y should be expressed as y = x + 1/x or y = (x + 1)/x.

PREREQUISITES
  • Understanding of polynomial equations, specifically quadratic equations like x^2 + x + G = 0.
  • Familiarity with algebraic manipulation of expressions involving cubes.
  • Knowledge of the properties of rational functions, particularly in the context of y = x + 1/x.
  • Basic skills in mathematical proof techniques, especially in algebra.
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  • Review the derivation of polynomial identities and their applications in algebra.
  • Study the properties of cubic equations and their factorizations.
  • Explore the implications of rational expressions and their simplifications.
  • Investigate common pitfalls in algebraic proofs to avoid misinterpretations.
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Students studying algebra, particularly those tackling polynomial equations and mathematical proofs, as well as educators looking for examples of common algebraic misunderstandings.

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Homework Statement



If x^2+x+G=0 and y=x+1/x , prove that Gy^3+(y-G)^3=0

Homework Equations





The Attempt at a Solution



Gy^3=x^5+3x^3+3x+1/x+x^4+3x^2+3+1/x^2

(y-G)^3=1/x^3+6/x+3+12x+12x^2+12x^4+6x^5+x^6

They are not equal.

Is this the correct way of doing ?
 
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Does
[tex]y = x + \frac{1}{x}[/tex]
OR
[tex]y = \frac{x + 1}{x}[/tex]
?


69
 
eumyang said:
Does
[tex]y = x + \frac{1}{x}[/tex]
OR
[tex]y = \frac{x + 1}{x}[/tex]
?


69

[tex]y=x+\frac{1}{x}[/tex]
 

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