Solve the given simultaneous equations in x^2, x and y

  • Thread starter chwala
  • Start date
  • #1
chwala
Gold Member
2,697
360
Homework Statement
See attached
Relevant Equations
Simultaneous equations
1693395998519.png
In my approach i have,

##\dfrac{x^2}{4} -1 = \dfrac{1}{y+1}##

##9-\dfrac{3}{2}=\dfrac{1}{y+1}##

then,

##\dfrac{x^2}{4} -1= 9-\dfrac{3}{2}##

##x^2-4=36-6x##

##x^2+6x-40=0##

##x_1=4, x_2=-10##

it follows that when ##x=4## then ##y+1=\dfrac{1}{3}## ⇒##y=-\dfrac{2}{3}##

and when ##x=-10## then ##y+1=\dfrac{1}{24}## ⇒##y=-\dfrac{23}{24}##

Seeking alternative ways...
 
Last edited:
Physics news on Phys.org
  • #2
I see no reason to hope there is a quicker way. Btw, you seem to have dropped 'x' in a couple of places when typing your post.
 

Similar threads

  • Precalculus Mathematics Homework Help
Replies
2
Views
380
  • Precalculus Mathematics Homework Help
Replies
10
Views
714
  • Precalculus Mathematics Homework Help
Replies
6
Views
682
  • Precalculus Mathematics Homework Help
Replies
3
Views
293
  • Precalculus Mathematics Homework Help
Replies
8
Views
677
  • Precalculus Mathematics Homework Help
Replies
5
Views
390
  • Precalculus Mathematics Homework Help
Replies
17
Views
555
  • Precalculus Mathematics Homework Help
Replies
4
Views
851
  • Precalculus Mathematics Homework Help
Replies
4
Views
792
  • Precalculus Mathematics Homework Help
Replies
8
Views
740
Back
Top