Can You Solve These Conservation of Energy Equations?

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SUMMARY

The discussion focuses on solving conservation of energy equations, specifically deriving the equation T = W(3 - 2cosO) from the initial equations T - W = (mv^2)/L and mgL(1 - cosO) = (mv^2)/2. The user successfully isolates T by substituting and manipulating the equations, ultimately confirming the relationship between tension (T), weight (W), and the angle (O). This step-by-step approach illustrates the application of energy conservation principles in physics.

PREREQUISITES
  • Understanding of conservation of energy principles
  • Familiarity with algebraic manipulation of equations
  • Knowledge of variables in physics such as tension (T), weight (W), mass (m), and gravitational acceleration (g)
  • Basic trigonometry, specifically the cosine function
NEXT STEPS
  • Study the derivation of energy conservation equations in classical mechanics
  • Explore the applications of tension in various physical systems
  • Learn about the role of trigonometric functions in physics problems
  • Investigate the implications of energy conservation in real-world scenarios
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of energy conservation and its mathematical applications.

blayman5
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I have to prove in a conservation of energy question

T-W =(mv^2)/L

mgL(1-cosO)=(mv^2)/2

mg=W

T=W(3-2Cos0)

How could I go about starting this?
 
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Assuming you can use the first three equations, use the first one to isolate T, then use the second one to get rid of the (mv^2) and finally replace the third one wherever possible. It should work out... just try it and post how far you get.
 
I got it:

T-W =(mv^2)/L
mgL(1-cosO)=(mv^2)/2

T=(mv^2)/L+W
mv^2=2mgL(1-cosO)
T=(2mgL(1-cosO))/L+W
T=(2W(1-cosO))/+W
T=2W-2WcosO+W
T=3W-2WcosO
T=W(3-2cosO)

Thanks
 

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