Can You Solve x|x+2|<5 by Subtracting 4?

[mathdad]

See picture for question.

View attachment 8538

 

[Joppy]

See picture for question.

You recently posted a question quite similar to this one and received a thorough answer. Could you highlight what you are having trouble with here?

 

[mathdad]

You recently posted a question quite similar to this one and received a thorough answer. Could you highlight what you are having trouble with here?

I was not able to read Country Boy's reply because his words blocked most of the LaTex.

 

[mathdad]

You recently posted a question quite similar to this one and received a thorough answer. Could you highlight what you are having trouble with here?

I made a typo. There should be no x in front of the absolute value bar.

Solution:

|x + 2| < 5

-5 < x + 2 < 5

-5 - 4 < x + 2 - 4 < 5 - 4

-9 < x - 2 < 1

a = -9, b = 1

Is this correct?

 

[mathdad]

You recently posted a question quite similar to this one and received a thorough answer. Could you highlight what you are having trouble with here?

A friend responded to my question this way:

|x + 2| < 5

-5 < x + 2 < 5

-5 - 4 < x + 2 - 4 < 5 - 4

-9 < x - 2 < 1

a = -9, b = 1

Is this correct?

Where did 4 come from in his reply?

 

[HOI]

Yes, that is correct. In the original problem, you were given information about x+ 2. The problem asked for information about x- 2. To go from x+ 2 to x- 2, you need to subtract 4: (x+ 2)- 4= x+ (2- 4)= x- 2.