How Do You Solve a Physics Problem Involving Forces and Motion?

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SUMMARY

The discussion centers on solving a physics problem involving forces and motion, specifically regarding a 14kg lawn mower being pushed with an 88N force at a 45-degree angle. Participants emphasize the importance of drawing a Free-body diagram to visualize the forces acting on the mower. Key calculations include determining the horizontal friction force, the normal force exerted by the ground, and the additional force required to accelerate the mower from rest to 1.5m/s in 2.5 seconds, factoring in the existing friction force.

PREREQUISITES
  • Understanding of Free-body diagrams
  • Knowledge of Newton's laws of motion
  • Familiarity with trigonometric functions (sine and cosine)
  • Basic principles of friction and normal force
NEXT STEPS
  • Learn how to draw and interpret Free-body diagrams in physics problems
  • Study the application of Newton's second law in calculating forces
  • Explore the concepts of static and kinetic friction
  • Practice solving problems involving acceleration and force calculations
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Students preparing for the Pharmacy College Admission Test (PCAT), physics learners, and anyone seeking to improve their problem-solving skills in mechanics and forces.

fishert16
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Cant figure out how to do this problem??

A person pushes a 14kg lawn mover at constant sped with a force of 88N directed along the handle, which is at an angle of 45 degress to the horizontal. (a) draw the Free-body diagram showing all forces acting on the mower. (b) Calculate the horizontal friction force on the mower, then (c) the normal force exerted vertically upward on the mower by the ground. (d) What force must the person exert on the lawn mower accelerate it from rest to 1.5m/s in 2.5 seconds, assuming the same friction force?

This is a problem on my practice PCAT test for Pharmacy school. And its been a while since I have had physics so any help would be appreciated.

Thanks
 
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Well, what have you done? Have you drawn a free body diagram at least? Which parts of the question have you attempted?
 
Because the angle of the handle is 45 degrees, the force along the handle of 88N can be broken up into a horizonal force or square root of 2x88; and a vertical downward force of the same amount. I.e. 1.414 x 88 = 124.4 N.

Nelson
 
Nelson,

er, that's close but sin and cos 45 are actually= sqrt(2)/2=1/sqrt(2)=.707

On the other post, I mentioned what the Normal force is, so can you calculate it? Hint: weight plus vertical component of push but directed upwards. So what is weight?
 

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