A person pushes a 16 kg lawn mower at a constant speed with a force of 80 N directed along the handle which is set at an angle of 45 degrees to the horizontal. If the coefficient of friction against the lawn mower is 0.230, what force must the person exert on the lawn mower to accelerate it from rest to 1.5 m/s over 3.0 m?? so i put the 80 N into a right triangle as the hypotenuse, and solved for the x and y terms and got 57 N. I then put it into a freebody diagram and and now stumped because i dont know what to solver for. If anyone could help its greatly appreciated! thanks!