Can't figure out how to solve a diffrential equation

  • Context: Undergrad 
  • Thread starter Thread starter johnt447
  • Start date Start date
  • Tags Tags
    Diffrential Figure
Click For Summary

Discussion Overview

The discussion revolves around solving a first-order linear differential equation of the form \(\frac{dv}{dt}=-\alpha v+\lambda F\), where \(\alpha\), \(\lambda\), and \(F\) are constants. Participants explore analytical methods for solving the equation, particularly focusing on the integrating factor method.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • The original poster expresses difficulty in solving the differential equation analytically after primarily using numerical methods.
  • One participant suggests using the integrating factor method, specifically multiplying through by \(e^{\alpha t}\) to simplify the equation.
  • The same participant indicates that the left side of the equation can be expressed as a derivative, which can then be integrated to find the solution.
  • Another participant provides links to external resources for further assistance with differential equations, including a website that computes DEs.
  • Subsequent replies acknowledge the usefulness of the suggested websites for checking answers and graphing solutions.

Areas of Agreement / Disagreement

Participants generally agree on the approach of using the integrating factor method, but there is no consensus on the completion of the solution or the correctness of the steps taken, as some participants refrain from fully solving the equation.

Contextual Notes

Some participants express uncertainty about the details of the integration process and the potential for mistakes in their calculations. The discussion does not resolve the specifics of the solution or the application of the method.

Who May Find This Useful

This discussion may be useful for students or individuals seeking assistance with first-order linear differential equations, particularly those interested in analytical methods and verification tools for their solutions.

johnt447
Messages
8
Reaction score
0
Hey

Not done this in ages and just can't figure it out, i need to solve the equation;

[itex]\frac{dv}{dt}=-\alpha v+\lambda F[/itex]

Where alpha,lambda and F are constants.

I'm so used to solving differential equations numerically i think I have forgotten how to do it analytically:P

My first attempt was looking at the integrating factor method although that seemed to get a bit messy think i might have messed it up a bit.
 
Physics news on Phys.org
ok to continue with your integrating coefficient method ... a good start would be to use e^αt and multiply that through the entire equation after you move the αv over to the left side.

dvdt=−αv+λFdvdt+αv=λF

e^αt dvdt + αv e^αt= λF e^αt

the left side is the derivative (chain/product rule) of some function: ddt (v e^αt) ... (since v is a function of t the chain + product rules both happen.) so if you rearrange the left side a bit and express it as a derivative like I said up there, then integrate both sides with respect to t, you'll have your solution.

I'm not going to finish the integration and algebra just due to whatever academic integrity forum rules there probably are, but you should get something in the general form of:

v = [v(0) - λF/α] e^-αt + λF/α

for v=v(0) at t = 0

... assuming I didn't make any silly mistakes or mistypes on my phone.

I hope that kinda helps more than it confuses
 
Last edited:
Thanks for the replies and that webstie to check DE is really useful.
 
johnt447 said:
Thanks for the replies and that webstie to check DE is really useful.

Yes it's a really cool tool for graphing and that kind of thing too. It pretty much does everything that you can think of, and usually shows its method.
 

Similar threads

  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K