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Capacitance of the capacitor after inserting the dielectric

  1. Apr 23, 2017 #1
    1. The problem statement, all variables and given/known data
    LVaWdkp.jpg

    2. Relevant equations
    V=Ed
    Q = CV
    W = 1/2 QV
    3. The attempt at a solution
    Hi. My instructor gave me this problem as a homework. Actually he didnt teach us this subject. So what should i know to solve this question or from where can i study to this subject? Of course it would be great if someone solve the problem but i dont want to take your time, just need the info of this subject to learn the subject and solve the problem. Thanks..
     
  2. jcsd
  3. Apr 23, 2017 #2

    kuruman

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  4. Apr 25, 2017 #3
    Thanks for the answer. After i learned the subject, i solved the problem. Then i noticed my answer is the same with answer on the pdf. (check image) I think it is the same question by the way. Isn't it?

    qD5g3A6.jpg
    kGkJqpw.jpg
     
  5. Apr 25, 2017 #4

    kuruman

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    Yes, it is the same. Note that the exact position of the dielectric does not affect the result as long as the dielectric surfaces are parallel to the plates.
     
  6. Apr 25, 2017 #5
    Im not sure i understood you. so does it change the result at my problem? Or you just said me that as an info? Sorry for my eng. Thanks btw you helped me a lot.
     
  7. Apr 25, 2017 #6

    kuruman

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    Just a point of information in case you see this again. The answer does not change,
     
  8. Apr 26, 2017 #7
    Thank you so much kuruman!
     
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