# Capacitor (currents, resistors, etC)

• nlsed
In summary, the conversation discusses a circuit involving a capacitor being charged through one bulb and then discharged through two bulbs. The statements being evaluated are: a) the same amount of charge flows during charging and discharging, b) more charge flows through the single bulb than through the two bulbs, c) charge flows at a greater flow through the single bulb than through the two, d) the single bulb shines brighter than either bulb in the two bulb circuit, e) the total resistance of the two bulbs is greater than that of the single bulb, f) a compass would show a larger deflection for the circuit with one bulb than the circuit with two, and g) the brightest bulb(s) indicate the fastest charge flow.After analyzing the

## Homework Statement

A capacitor is charged through one bulb and then discharged through two bulbs. Mark each of the following statements true or false.

a) The same amount of charge flows during charging and discharging.
b) More charge flows through the single bulb than through the two bulbs.
c) Charge flows at a greater flow through the single bulb than through the two.
d) The single bulb shines brighter than either bulb in the two bulb circuit.
e) The total resistance of the two bulbs is greater than that of the single bulb.
f) A compass would show a larger deflection for the circuit with 1 bulb than the circuit with two.
g) The brightest bulb(s) indicate the fastest charge flow.

## The Attempt at a Solution

a) I am pretty sure this is true because bulbs don't affect amount of charge, but does it affect flow rate??, and i am wondering how much charge is on the + and - ends of the capacitor... and after the discharge is all the charge back on the negative side?
b) Is it false because the same amount of charge gets through, but at a slower rate?
c)True, because the resistance is higher in two bulbs, slowing down the flow rate
d)True, because the flow rate is less than the single bulb. less resistance more brighter right?
e)True, Dont need help with this 1 :)
f) True because there is less charge per second in the wire creating less of a disturbance in the field?? i don't know why.
g)True, less resistance, faster flow = brighter

PLEASE TELL ME IF IM WRONG

The answers will vary depending on whether the bulbs are in series with the capacitor, or in parallel. Can you clarify?

the bulbs are in a series. the 1st diagram is just

wire connecting bulb to batteries and a wire connecting the bulb to the + side of the capacitor. a wire connecting battery to capacitor on - side.

2nd diagram is
wires connecting + and - side of the capacitor with 2 bulbs in between them