(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Capacitors C1 = 5.95 μF and C2 = 1.90 μF are charged as a parallel combination across a 277 V battery. The capacitors are disconnected from the battery and from each other. They are then connected positive plate to negative plate and negative plate to positive plate. Calculate the resulting charge on capacitor C1.

2. Relevant equations

Q=C/V

3. The attempt at a solution

This is as far as I got, but i'm guessing I went wrong somewhere.

Calculate equivalent capacitance

C_{t}= C_{1}+ C_{2}= 7.85μF

Calculate total charge on the capacitors

Q_{t}= C_{t}/V = 0.002174 C

Charge on C_{1}is half of the total, or 0.001087 C

Calculate voltage on C_{1}

V_{1}= Q_{1}/C_{1}= 182.7 volts

I am stuck from here though, even if what I've done so far is right, I have no idea where to go.

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# Homework Help: Capacitors in paralell disconnected then connected to each other

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