Car accelerating uniformly for 6s - kinematics

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Homework Help Overview

The problem involves a car that accelerates uniformly from rest over a period of 6 seconds, with a focus on comparing the distance traveled in the first second to the total distance traveled in the 6 seconds. The subject area is kinematics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using kinematic equations to find distances at different times and question how to approach the problem without knowing the acceleration or final position.

Discussion Status

The discussion is active, with participants exploring the relationship between distance traveled and acceleration. Some guidance has been offered regarding the use of kinematic equations, but there is no consensus on how to proceed given the unknowns.

Contextual Notes

Participants note the constraints of not knowing the acceleration and final position, which are necessary for applying the kinematic equations effectively.

krazykaci
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A car starts from rest and accelerates uniformly for 6s. The distance traveled in the 6s is greater than the distance traveled in the 1st second by a factor of what?

how would i go about doing this?
 
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Use the equation of kinematics at constant acceleration:

x(t)=x_0+v_0t+\frac{a}{2}t^2

Find x(6) and x(1). Then find the factor k such that x(6)=k*x(1). Makes sense?
 
Use your kinematic equation for distance.
 
ok I am going to say what i know

v.=0
t=6s
x.=0
a=unknown
but what would final x be?
 
final x is given by the equation of kinematics.. this is what it says: "give me an initial position, initial velocity and a time and I'll give you a final x"
 
but how can i use the equation when i don't know a, or final x and both are in the equation?
 
a is constant right? So its just a proportion. The answer will have accelerration in it.
 

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