Car going around banked curve with no friction

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Homework Help Overview

The problem involves a car negotiating a banked curve with a specified radius and angle, focusing on determining the maximum speed without friction. The subject area includes dynamics and circular motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the formula relating banking angle, speed, and radius. There are questions regarding the correctness of the calculated speed and the units used. Some participants attempt to clarify the reasoning behind the formula and its derivation.

Discussion Status

There is an ongoing exploration of the formula's application and the calculations involved. Some participants express confusion about the underlying concepts, while others provide supportive feedback and clarification on the formula's components.

Contextual Notes

Participants mention a lack of understanding regarding the derivation of the formula and express concerns about their grasp of the material, indicating that the problem is part of a broader learning context involving quizzes and classroom instruction.

chaotiiic
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Homework Statement


a racecourse is designed with curves with a radius of 200m and a 10degree banking. What is the maximum speed a car can negotiate the curve without friction?


Homework Equations


Newtons 3 laws


The Attempt at a Solution


tanTheta = v^2/gR
tan10 = v^2/(9.8 * 200m)
v = 345 m/s^2

is this right?
 
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hi chaotiiic! :smile:
chaotiiic said:
tanTheta = v^2/gR
tan10 = v^2/(9.8 * 200m)

formula looks ok

are you sure about the 345 ?

(and speed is m/s, not m/s2)
 
tiny-tim said:
hi chaotiiic! :smile:


formula looks ok

are you sure about the 345 ?

(and speed is m/s, not m/s2)

so is it 0.1763 = v^2/1960
v^2=345.6
v=18.59m/s
 
yes! :smile:

(are you ok now, or is there anything you're still not sure about?)​
 
tiny-tim said:
yes! :smile:

(are you ok now, or is there anything you're still not sure about?)​

thankyou.
im actually still confused about everything. the only reason i was able to answer this problem is because there's a problem identical in my book to the one i asked. my teacher gives out quizzes before lectures so hopefully ill understand when i go to class later today.
 
ok, so you don't understand the reason for the formula? …
chaotiiic said:
tanTheta = v^2/gR

like almost all dynamics questions, it all boils down to good ol' Newton's second law (F = ma) …

you know the acceleration (as a function of v),

and although you know the weight, you don't know the normal force …

so you do F = ma perpendicular to the unknown (normal) force :smile:
 

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