Cartesian equation of plane using two lines?

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alakd
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Can someone help with this multi-part question. i did the first three but it doesn't seem right!
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(a) Find the equation of the line l through P(1, 1, 2) and Q(1, 0, 4) in vector, parametric and Cartesian forms.
(b) Find the vector form of the line k through R(0, 3, 1) which is perpendicular to l.
(c) Find the Cartesian form of the plane containing the lines l and k.
(d) Find the vector form of the line through T(0, 0, 3) which is normal to this plane.
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so i guess i did the first bit alright : cartesian : z=6+4x , y=6
for the second one i got this line : (-5,4,2)+t(28,-37,7) , i timed it by 17 to get rid of the denominator
third part : the lines seem to have no intersection so i am stuck!

appreciate it if anyone can help out
 
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alakd said:
Can someone help with this multi-part question. i did the first three but it doesn't seem right!
--------------------------------------…
(a) Find the equation of the line l through P(1, 1, 2) and Q(1, 0, 4) in vector, parametric and Cartesian forms.
(b) Find the vector form of the line k through R(0, 3, 1) which is perpendicular to l.
(c) Find the Cartesian form of the plane containing the lines l and k.
(d) Find the vector form of the line through T(0, 0, 3) which is normal to this plane.
--------------------------------------…
so i guess i did the first bit alright : cartesian : z=6+4x , y=6
To which is this an answer? Clearly not (a) because x is always equal to 1 but y is NOT always equal to 6 and z is not always equal to 6+ 4(1)= 10.

for the second one i got this line : (-5,4,2)+t(28,-37,7) , i timed it by 17 to get rid of the denominator
third part : the lines seem to have no intersection so i am stuck!

appreciate it if anyone can help out
It's impossible to tell what you are saying because you talk about ""first", "second", and "third" when the problems are labeled "a", "b", "c", and "d" and "a" has three parts!