# Cartesian equation of plane using two lines?

1. Apr 28, 2012

### alakd

Can someone help with this multi-part question. i did the first three but it doesnt seem right!
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(a) Find the equation of the line l through P(1, 1, 2) and Q(1, 0, 4) in vector, parametric and Cartesian forms.
(b) Find the vector form of the line k through R(0, 3, 1) which is perpendicular to l.
(c) Find the Cartesian form of the plane containing the lines l and k.
(d) Find the vector form of the line through T(0, 0, 3) which is normal to this plane.
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so i guess i did the first bit alright : cartesian : z=6+4x , y=6
for the second one i got this line : (-5,4,2)+t(28,-37,7) , i timed it by 17 to get rid of the denominator
third part : the lines seem to have no intersection so i am stuck!

appreciate it if anyone can help out

2. Apr 29, 2012

### HallsofIvy

To which is this an answer? Clearly not (a) because x is always equal to 1 but y is NOT always equal to 6 and z is not always equal to 6+ 4(1)= 10.

It's impossible to tell what you are saying because you talk about ""first", "second", and "third" when the problems are labeled "a", "b", "c", and "d" and "a" has three parts!