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## Main Question or Discussion Point

I am having trouble finding the Cartesian equation of the line k which passes through Y(0,1,0) and is normal to -3x-2y+2z=0

this is what I tried to do but not sure if it is the correct method

normal direction (-3,-2,2)

-3x-2y+2z=d

sub in (0,1,0) to -3x-2y+2z=d

d=-2

-3x-2y+2z=-2

is this correct if so how would i get it into cartesian form?

this is what I tried to do but not sure if it is the correct method

normal direction (-3,-2,2)

-3x-2y+2z=d

sub in (0,1,0) to -3x-2y+2z=d

d=-2

-3x-2y+2z=-2

is this correct if so how would i get it into cartesian form?