1. The problem statement, all variables and given/known data Catapult A catapult on a cliff launches a large round rock towards a ship on the ocean below. The rock leaves the catapult from a height H = 35.0 m above sea level, directed at an angle theta = 48.7° above the horizontal, and with a speed v = 26.1 m/s. Assuming that air friction can be neglected, calculate the horizontal distance D traveled by the projectile. 2. Relevant equations y=y0+Vy0t-1/2gt^2 x=x0+ Vx0t 3. The attempt at a solution Ok, So I plugged in my knowns to find the time for this, using the first equation setting it up like this 4.9t^2-19.6t+35, where vy0t=26.1*sin48.7 gave me 19.6 then I plugged in my values to the Quadratic formula where the answers I got were 2.97 and 1.03 respectively to find time, so I use the lower of the two numbers and I plug it back into x=x0+Vx0t, since intial D is 0 you add 26.1*cos(48.7) to give 17.2 then you times it to the time calculated 1.03 to get 17.72 m...its not right, I don't understand where I am going wrong Ive set it up 7 different ways... This seems like a relatively easy question I only have 2 more tries left on it out of 10. Would someone point me in the right direction Im getting frustrated at this point and feel like and idiot considering its only ch.2.