Standard Reduction Potential Changes in Regards to Acidity

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Discussion Overview

The discussion centers on the effect of pH changes on the standard reduction potential of the half-reaction involving the reduction of O2 to H2O in an acidic solution. Participants explore the application of the Nernst equation in this context, particularly how an increase in pH affects the half-cell potential at 25 °C.

Discussion Character

  • Homework-related, Technical explanation

Main Points Raised

  • One participant states that the reaction quotient would be 0 due to the presence of a pure liquid on the product side.
  • Another participant corrects this by noting that the activity of a pure substance is not zero.
  • A subsequent participant questions whether the activity of the pure liquid would be 1, expressing uncertainty.
  • Another participant confirms that the activity is indeed 1, drawing a parallel to the activity of solids in solubility product calculations.

Areas of Agreement / Disagreement

Participants generally agree on the activity of pure substances being 1, but there is uncertainty regarding the application of the Nernst equation and the implications of pH changes on the half-cell potential.

Contextual Notes

Limitations include the need for clarity on how to apply the Nernst equation in this scenario and the assumptions regarding the reaction quotient.

Teemo
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Homework Statement


The reduction of O2 to H2O in acidic solution has a standard reduction potential of +1.23 V. What is the effect on the half-cell potential at 25 °C when the pH of the solution is increased by one unit?

O2(g) + 4H+(aq) + 4e- –> 2 H2O(l)

(A) The half-cell potential decreases by 59 mV.
(B) The half-cell potential increases by 59 mV.
(C) The half-cell potential decreases by 236 mV.
(D) The half-cell potential increases by 236 mV.

Homework Equations


Nernst Equation

The Attempt at a Solution


I'm aware this is a Nernst equation problem. Yet, I'm not exactly sure how to apply it. It appears to me that the reaction quotient would be 0, since there is only a pure liquid on the product side. As such, I am not sure how to approach the problem.
 
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Teemo said:
quotient would be 0, since there is only a pure liquid on the product side

Activity of a pure substance is not zero.
 
Would it be 1? I feel like I'm missing something obvious o_O
 
Yes, it is 1. Just like activity of solids (think Ksp - it doesn't contain solid, as its activity is 1).
 
Thank you so much!
 

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