Centre of Mass/Tipping Point Question

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Homework Statement
The top deck of a bus is loaded with sandbags. The bus is tested to ensure all 4 wheels are in contact with the ground up, to at least 280 degrees to the vertical. The height of the bus is 4.4m and width is 2.4m. Calculate the height of the centre of mass of the loaded bus by assuming it would topple over at larger angles.
Relevant Equations
h = 1.2tan(10)
Handwritten working on a tipping box problem: a tilted box on a surface with a ball at its centre, a 10 degree angle marked, a right triangle with sides h and 1.2 and angle 10 degrees, and the equation h = 1.2 tan(10).

I drew out a small diagram to illustrate my attempt. I interpreted 280 degrees from the vertical as 10 degrees from the horizontal. Using trig I solved for the h, which I get an obviously incorrect answer. The actual answer in the book is 2.3m,
 
I believe that you have misread the question or that it has been poorly transcribed. It is not 280 degrees. It is 28 degrees (28°)

One can easily imagine a transcription error where a degree symbol is rendered as the digit zero.
https://www.quora.com/Why-do-double-decker-buses-not-tip-over said:
In the UK, British transportation regulations required that double decker buses be tested on a tilting ramp, to an angle of 28-degrees.
Note that this is 28 degrees from the vertical, not 10 degrees from the horizontal. So the relevant formula will change slightly from the one you have used.

With those tweaks in mind, I get the book answer to two significant digits.

Edit to add graphical image
https://www.ltmuseum.co.uk/collections/collections-online/photographs/item/2002-18969 said:
Photo of a red London double-decker bus with registration 39 CLT tilted on a sloped test platform inside a workshop, with a tilt gauge scale marked 40, 30, 20, 10, 0 beside it.
 
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jbriggs444 said:
I believe that you have misread the question or that it has been poorly transcribed. It is not 280 degrees. It is 28 degrees (28°)

One can easily imagine a transcription error where a degree symbol is rendered as the digit zero.

Note that this is 28 degrees from the vertical, not 10 degrees from the horizontal. So the relevant formula will change slightly from the one you have used.

With those tweaks in mind, I get the book answer to two significant digits.
Thank you, after re-calculating I get 2.256..., which is consistent with the answer to 2.s.f. It unfortunately appears to be a printing error.
 
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