(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A geostationary satellite goes around the Earth in 24hr. Thus, it appears motionless in the sky and is a valuable component for telecommunications, including digital television. If such a satellite is in orbit around the Earth at an altitude of 35 800 km above the Earth's surface, what is the module of its centripetal acceleration?

2. Relevant equations

I believe I should use

a_{c}= (4∏^{2}r) / T^{2}

Converted:

T= 24 hr = 86400s

r = 35800 km = 35 800 000 m = 3.58 x 10^{7}m

3. The attempt at a solution

I plugged in the values:

a_{c}= (4∏^{2}35 800 000) / 86400^{2}

a_{c}= 0,189

The answer SHOULD be 0.223 m/s^{2}

Help!

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# Centripetal acceleration of an orbit to the earth... help!

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