Centripetal Force and maximum speed

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Homework Help Overview

The problem involves a motorcyclist approaching a hump-backed bridge, which is modeled as part of a circular path. The task is to determine the maximum speed at which the rider can travel without losing contact with the road at the top of the bridge, given specific parameters such as the radius of the bridge and the mass of the motorcycle and rider.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need for assumptions regarding static friction and explore the application of conservation of energy principles. Questions are raised about the forces acting on the motorcycle, particularly the role of friction.

Discussion Status

Some participants have suggested using conservation of energy to relate kinetic and potential energy, while others are questioning the forces involved in maintaining contact with the road. There is an ongoing exploration of different interpretations of the problem, but no consensus has been reached.

Contextual Notes

There is mention of missing information regarding the coefficient of static friction and assumptions about its negligible effect. Participants are also considering the implications of the conservation equations in their reasoning.

kingyof2thejring
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A motorcyclist is approaching a hump-backed bridge, as shown in the diagram. The bridge forms part of a circle of radius r = 14.4 m. The combined mass of the motorcycle and rider is 141 kg. Calculate the maximum speed in m s-1 at which the rider could travel without leaving the road at the top of the bridge.

How do i go about workin this one out without knowing Fmax and u\mu[\tex] coeff static friction. Thanks in advance
 
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If it's not given, I guess you get the pleasure of assuming that it is negligible.

Apply conservation of energy: kinetic energy will be less at the top of the hump.

Check if the velocity is less than which is required for circular motion.
 
What is the force keeping him on the road? It's not friction.

EDIT: Just seconds slower than mezarashi :smile:
 
Last edited:
so mgh=0.5mv^2
and v=16.8
 
Päällikkö said:
What is the force keeping him on the road? It's not friction.

EDIT: Just seconds slower than mezarashi :smile:

Sorries! >.<
 
kingyof2thejring said:
so mgh=0.5mv^2
and v=16.8

You have the car coming at a certain velocity. Apply the conservation equation.

KE1 + PE1 = KE2 + PE2

The potential PE1 is zero, we consider ground. The potential at PE2 is mgh. We know KE1, find KE2. Use KE2 in your next step.
 
cheers mate mezarashi
its best to consider the moition using that equation
 

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