Given speed/mass find R (centripetal)

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SUMMARY

The discussion addresses a physics problem involving centripetal force and motion over a road hump. For a 50kg person driving at 8.3 m/s, the radius of the hump is calculated to be 9.93 meters using the formula R = (mv²)/(mg - FN), where FN is the normal force felt by the driver. Additionally, to achieve a state of weightlessness at the top of the hump, the required speed is determined to be 9.86 m/s, derived from the equation v = (gR)^(0.5). The calculations for both the radius and the speed are confirmed to be correct.

PREREQUISITES
  • Understanding of centripetal force and acceleration
  • Familiarity with Newton's second law of motion
  • Knowledge of basic physics equations involving mass, velocity, and radius
  • Ability to manipulate algebraic equations for problem-solving
NEXT STEPS
  • Study the concept of centripetal acceleration in more detail
  • Learn about the implications of varying mass and speed on centripetal force
  • Explore real-world applications of centripetal motion in vehicles
  • Investigate the effects of different road conditions on vehicle dynamics
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of motion and forces acting on vehicles.

jybe
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Homework Statement


1) A 50kg person drives a car at 8.3m/s over a hump in the road. At the top of the hump, the driver feels a force of 143 N from the seat. What is the radius of the hump?

2) At what speed will the car need to move over the hump for the person to feel weightless at the top?

Homework Equations


Fc = (mv2)R

The Attempt at a Solution


1)

Fc = mac
mg - FN = (mv2)/R
R = (mv2)/(mg - FN)
R = 9.93 m

2)

g = v2/R (total centripetal acceleration must be equal to gravity)
v = (gR)0.5
v = 9.86 m/s

Pretty sure #2 is right, but did I get the correct radius in #1?
 
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jybe said:
did I get the correct radius in #1?
Yes, you did.
 

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