- #1

Chelonian

- 10

- 0

2/(a-1)^2+9b+9c-d=0

2/(b-1)^2+9a+9c-d=0

2/(c-1)^2+9a+9b-d=0

1-a-b-c=0

It should be noted that a, b, and c are all positive numbers, and, therefore, must all be less than one. The solution is a=b=c=1/3, d=21/2, I just don't know how to get that.

I greatly appreciate any help you can give to me for this problem. Thank you for your time.

P.S. I hope this is the right section for this type of question, but I am very new here, so please forgive me if I was wrong.