Change of variables in Seocnd order ODES

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SUMMARY

The discussion focuses on the process of changing variables in second-order ordinary differential equations (ODEs), specifically transforming the modified Bessel's equation into Bessel's equation using the substitution t=ix. The equation in question is (x^2)y''+(x)y'-(x^2+p^2)y=0. The user seeks clarity on how to correctly apply the change of variables, particularly in differentiating y with respect to x and t. Key transformations include dt=idx and the implications for first and second derivatives of y.

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  • Understanding of second-order ordinary differential equations (ODEs)
  • Familiarity with Bessel's equations and modified Bessel's equations
  • Knowledge of complex variable substitution techniques
  • Proficiency in differentiation and chain rule applications
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  • Study the derivation and properties of Bessel's equations
  • Explore complex variable substitution in differential equations
  • Learn about the chain rule in the context of variable transformations
  • Practice solving second-order ODEs with various substitutions
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Students of mathematical physics, mathematicians, and anyone involved in solving second-order ordinary differential equations, particularly those interested in variable transformations and Bessel functions.

phil ess
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I am looking through my course notes for mathematical physics, in preparation for the exam, and I've run into a concept that I can't figure out. It comes up first when talking about the modified bessel's equation

(x^2)y''+(x)y'-(x^2+p^2)y=0

And supposedly this can be transformed into bessel's euqation by using the substitution t=ix, but I can't figure out how this works. This is just the specific example that this issue came up in; I don't understand generally how to perform a change of variables for second order equations.

I start with dt=idx and -t^2=x^2, but how do I deal with y'' and y'?

If anyone can explain how change of variables works to me it would be greatly appreciated!
 
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dt = i dx
dx = -i dt

dy/dx = dy/(-i dt) = i dy/dt

d²y/dx² = d(dy/dx)/dx = d(i dy/dt) / (-i dt) = - d²y/dt²
 

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