Changing components back into general

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Homework Help Overview

The discussion revolves around a physics problem involving the calculation of kinetic energy for a box being pulled up a ramp, with specific attention given to the acceleration components in different directions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore how to convert acceleration in the x direction to a general acceleration, with one participant questioning the meaning of 'regular acceleration'. Others discuss the forces acting on the box and the calculations involved in determining kinetic energy.

Discussion Status

Some participants have provided guidance on identifying forces and setting up equations related to work and energy. There is an ongoing exploration of the relationships between different components of acceleration and how they relate to the overall problem.

Contextual Notes

Participants note the specific parameters of the problem, including the weight of the box, the angle of the ramp, and the coefficient of kinetic friction. There is a mention of homework constraints and the need for clarity in understanding the problem setup.

themusicman118
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i am having a little problem.

i have the acceleration in the x direction for an object but do not know how to change it back to regular acceleration.

please help
 
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themusicman118 said:
i am having a little problem.

i have the acceleration in the x direction for an object but do not know how to change it back to regular acceleration.

please help

What exactly do you mean by 'regular acceleration'?
 
Amendment to Earlier Question

Sorry, i am new to this. Here is requested info.


Homework Statement


An 80.0 N box of clothes is pulled 20.0 m up a 30.0 degree ramp by a force of 115 N that points along the ramp. If the coefficient of kinetic friction between the box and the ramp is 0.22, calculate the change in the box's kinetic energy


Homework Equations


I started by back tracking to find the mass (m=f.w./g)

Then tried to solve for the sum of the forces in the x direction by doing sigma Fx = -Fw,x+Fp,x

I solved for Fw,x by

Fw,x = Fw*sin theta

and Fp,x by

Fp,x = Fp*cos theta

got Fx = -40 + 69.28 = 29.28 N

From Fw,x I solved for a,x with

a,x = ΣF,x/m

a,x = 3.59 m/s2

The Attempt at a Solution



is it

a,x = a cos theta

a = a,x/cos theta

a = 3.59/ cos 30 degrees

a = 4.15 m/s2

??
 
please see new thread 'Amendment to Earlier Question'


Thanks
 
themusicman118,

Rather than starting a new thread, please just continue in the same thread you've already created for this question. I have merged the threads together. Please do not create another one.

- Warren
 
The change of the kinetic energy of the box equals the work done by all forces along the displacement. Identify the forces acting on the box, draw a free body diagram, and set up the equation of work.
 
thanks for the help

will be back in a little while
 
Will let you know the results after i receice the homework assignment back on Monday.
 
Thanks to everyone who helped out. I turned in my homework today, after staying up till 10:46 last night
 
  • #10
thanks to all who helped
 

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