Characteristic polynomial splits into linear factors

Click For Summary
SUMMARY

The characteristic polynomial of an n by n matrix over GF(q) indeed splits into linear factors over GF(q^n). This holds true regardless of whether the polynomial is irreducible or reducible. When considering an irreducible polynomial p of degree k over GF(q), its splitting field over GF(q) consists of all roots of p, which are contained within an extension field of GF(q).

PREREQUISITES
  • Understanding of finite fields, specifically GF(q)
  • Knowledge of characteristic polynomials and their properties
  • Familiarity with irreducible polynomials and splitting fields
  • Basic concepts of field extensions in algebra
NEXT STEPS
  • Study the properties of finite fields, particularly GF(q^n)
  • Learn about irreducible polynomials and their role in field theory
  • Explore the concept of splitting fields in algebra
  • Investigate the relationship between matrices and their characteristic polynomials
USEFUL FOR

Mathematicians, algebra students, and researchers in field theory or linear algebra who are exploring the properties of characteristic polynomials and finite fields.

Hello Kitty
Messages
25
Reaction score
0
Is it true that the characteristic polynomial of an n by n matrix over GF(q) splits into linear factors over GF(q^n)?

I see that it must do if the polynomial is irreducible but what if it isn't?
 
Physics news on Phys.org
Let p be an irreducible polynomial of degree k over GF(q). What does the splitting field of p (over GF(q)) look like?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K