Charge and Voltage ProblemDon't know where to start

[JoshP-hillips]

Homework Statement

The charge Q of the semiconductor diod has been shown through experiment to vary with the applied voltage V. This relationship can be expressed as:

Q(V) = Q₀ ln(1 + V/V₀)

Where Q₀ and V₀ are some constant reference values measured in Coulombs and Volts correspondingly.

From testing it was found that the charge Q was 2 times greater than Q₀ when the applied voltage V was 4.792V and the charge was 2.6x10^-5 C when the applied voltage was 2V

a) Find the values of Q₀ and V₀ indicating their dimensions (2 decimal places). Write Q as a function of V

b) What is the charge on the diod when the applied voltage is 3V? (2decimal places)

c) Find the voltage which must be applied to get the charge Q = 1.3x10^-5 C

Homework Equations

Provided above

The Attempt at a Solution

Q(4.792) = Q₀ln(1 + 4.792/V₀)So I got this far, but I'm not sure how to solve for Q₀ and V₀ at the same time in one equation.

Any and all advice on where to go or what to do to get moving would be fantastic.

 

[gneill]

Concentrate on this bit first: "From testing it was found that the charge Q was 2 times greater than Q₀ when the applied voltage V was 4.792V".

You should be able to write the equation so that V₀ is the only unknown.