Charge released from rest near a grounded conductor

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Homework Help Overview

The problem involves a charge released from rest near a grounded conductor, specifically a semi-infinite conductor. The objective is to determine the time it takes for the charge to reach the conductor.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the method of images to find the force acting on the charge. Some participants question how to proceed from the force equation to find the time taken for the charge to reach the conductor.

Discussion Status

Participants are exploring different aspects of the problem, including the relationship between force and motion. Some guidance has been offered regarding expressing the force as a function of the variable distance to the conductor and deriving an equation for velocity.

Contextual Notes

There is a focus on integrating the force to find the motion of the charge, with some participants expressing uncertainty about the integration process and the implications of treating distance as a variable.

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Homework Statement


A charge q of mass m is released a distance d from a semi-infinite grounded conductor. How long will it take the charge to reach the conductor?

So I tried this using the method of images, and I can easily find the force on the charge a distance d away:

F = -q^2 zhat / (4 pi epsilon0 (2d)^2)

But I'm not sure where to go from here.

Any help would be fantastic
 
Last edited:
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[tex]F= - \frac{q^2}{4 \pi \epsilon_0 (2d)^2}\hat{z}[/tex]
[tex]F = m \frac{\partial^2 r}{\partial t^2}[/tex]

Does this help??

Sam =]
 
Not really, I'm aware of the definition of Force. If you'd like to show how to integrate that I'd be grateful, but I have no idea.
 
d is a constant here: instead, write the force as a function of the variable z (the variable distance to the conductor). Then, as an intermediate step, can you get an equation for the velocity dz/dt of the charge as a function of z?
 
Thanks that was what I needed to do.

Just as a followup:
change second derivative of z to dv/dz*dz/dt=dv/dz*v
from there it's pretty easy
 

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