[Chem] Ions' States of Matter when not in solution

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SUMMARY

The discussion centers on the decomposition of hydrogen peroxide (H2O2) into water (H2O) and oxygen gas (O2) through a catalytic process. The molecular formula for this reaction is 2 H2O2 (l) → 2 H2O (l) + O2 (g). The oxidation and reduction half-reactions are identified as follows: reduction involves O22- + 2 e- → 2 O22- and oxidation is O22- → O2 (g) + 2 e-. The state of the peroxide ion is clarified to be aqueous due to the nature of hydrogen peroxide as an aqueous solution.

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Homework Statement



Hydrogen peroxide decomposes into water and oxygen gas with the help of a catalyst. write the molecular formula and the redox half reactions.

Homework Equations



(N/A)


The Attempt at a Solution



the molec. formula is of course

2 H_{2}O_{2} (l) \stackrel{catalyst}{\rightarrow} 2 H_{2}O (l) + O_{2} (g)

now for the reduction and oxidation half reactions:

reduction
O^{2-}_{2} + 2 e^{-} \rightarrow 2 O^{2-}

oxidation
O^{2-}_{2} \rightarrow O_{2} (g) + 2 e^{-}


My question is, what states should each of these ions in the half reactions be in? Normally (like for double displacement rxns) I know the ions are aqueous, but that's when both reactants are aqueous/in solution. Should the peroxide ion here, for instance, be liquid (because hydrogen peroxide is a liquid) or should it be aqueous?

Thanks in advance! :smile:
 
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If i understand you question correctly then the peroxide would be aqueous because hydrogen peroxide is a very blue liquid if I'am remembering right but peroxide is an aqueous solution of hydrogen peroxide. I'm pretty sure that what I said is correct but look it up in a textbook to be safe.
 

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