Chemistry Balancing Redox Reactions

[frozonecom]

Homework Statement

$$H_{2} + O_{2} \rightarrow H_{2}O$$

Homework Equations

The Attempt at a Solution

Well, my classmates insist that H= +1 and O= -2 (in the products side)
so, my Hydrogen will be my Reducing agent because it underwent Oxidation and my Oxygen will be my Oxidizing agent because it underwent Reduction

Reduction: $$O_{2} \rightarrow H_{2}O$$
Oxidation: $$H_{2} \rightarrow H_{2}O$$

From here on, I can't understand anything.

Well, I need to know what to do here. I was told by this video:

https://www.youtube.com/watch?v=AyKiYz-YpSw

Particularly in 4:09, in that problem, she said that $$H_{2}O$$ has a charge of 0. I know that Hydrogen and Oxygen in the reactants side has 0 charge / oxidation number too because it is in its "pure" form. So, is this equation "BALANCE-able" ??

 

[Borek]

Molecule of H₂O is neutral (has a charge of 0), but oxidation numbers of oxygen and hydrogen in the molecule are -2 and +1 respectively. They just cancel out in the molecule.

 

[frozonecom]

Molecule of H₂O is neutral (has a charge of 0), but oxidation numbers of oxygen and hydrogen in the molecule are -2 and +1 respectively. They just cancel out in the molecule.

ooh. Now I get it. Sorry for the dumb question. She just did it faster and not saying that the charges cancel each other. Thanks. :)
But, what is the overall reaction? The balanced one with the electrons and such. I can't understand it.

 

[Borek]

I don't like the video, it is slightly chaotic.

While H₂/O₂ is a redox reaction, trying to balance it as a redox is a waste of time. Are you asked to balance it as redox, or just to balance? Final effect will be exactly the same.

 

[frozonecom]

I don't like the video, it is slightly chaotic.

While H₂/O₂ is a redox reaction, trying to balance it as a redox is a waste of time. Are you asked to balance it as redox, or just to balance? Final effect will be exactly the same.

Yeah, we are asked to balance it (as in moles)
then as redox. Sorry for the late reply.