Chemical Equation: Dissociating PbBr2 - Ksp of 6.3E-6

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Discussion Overview

The discussion revolves around the dissociation of lead (II) bromide (PbBr2) in water and the corresponding solubility product constant (Ksp) of 6.3E-6. Participants are exploring the chemical equation for the dissociation process and addressing the solubility of PbBr2.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant states the Ksp of lead (II) bromide is 6.3E-6 and asks for the chemical equation for its dissociation.
  • Another participant inquires about the ions present in PbBr2.
  • A different participant asserts that there are no ions, only PbBr2 is shown.
  • Another reply challenges this assertion, reminding that PbBr2 is an ionic compound and suggests reconsidering the original question regarding its dissociation.
  • The same participant notes that PbBr2 is slightly soluble, implying that the dissociation should be considered.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the presence of ions in PbBr2, with conflicting views on whether it can be dissociated in the context of the Ksp provided.

Contextual Notes

The discussion includes assumptions about the solubility of PbBr2 and the interpretation of its dissociation in water, which remain unresolved.

kokenwa
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the Ksp of lead (II) bromide is 6.3E-6. A large amount of PbBr2 sits at the bottom of a beaker with water above it. Equilibrium is reached. Write the chemical equation fo rthe dissociation of lead II bromide as it dissolves for which the Ksp applies.


-How would i go about solving this problem?
 
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What are the ions in PbBr2?
 
there are none. it just shows PbBr2
 
kokenwa, rethink eli64's question. PbBr2 is an ionic compound, so you should be able to answer his question. Also, PbBr2 is slightly soluble, therefore you should think through to your original question.
 

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