Chemical Equilibrium and Concentration

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SUMMARY

The equilibrium constant for the reaction between hydrogen and fluorine, represented by the equation H2(g) + F2(g) -> 2HF(g), is 1.15x102 at a specific temperature. To calculate the equilibrium concentration of HF after adding 3.00 mol of each reactant to a 1.500 L flask, the initial concentrations of H2 and F2 are both 2 M. The equilibrium concentration of HF is determined to be 1.5 M, highlighting the necessity of using an ICE table to account for changes in concentration at equilibrium. The discussion emphasizes that ICE tables are not suitable for buffer solution calculations.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Familiarity with the ICE table method for equilibrium calculations
  • Knowledge of equilibrium constants and their significance
  • Basic skills in stoichiometry and concentration calculations
NEXT STEPS
  • Study the application of ICE tables in various chemical reactions
  • Learn about the Henderson-Hasselbalch equation for buffer solutions
  • Explore the implications of equilibrium constants in chemical reactions
  • Investigate the differences between strong and weak acids/bases in equilibrium
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Chemistry students, educators, and professionals involved in chemical equilibrium studies, particularly those focusing on reaction dynamics and concentration calculations.

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The reaction between hydrogen and fluorine has an equilibrium constant of 1.15x102 at a certain temperature. Given the reaction equation H2(g) + F2(g) -> 2HF(g), calculate the equilibrium concentration of HF after 3.00 mol of each component is added to a 1.500 L flask.

I attempted solving it by calculating the concentration of H2 and F2 which were each 2 (3/1.5). Afterwards, I formed the equilibrium expression and multiplied 2 squared (for H2 and F2) with 1.15x102. Then I found the square root of the answer since HF would be raised to the power of 2 which was about 21. However, the answer is 1.5M and I don't know how they got that.
 
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Hydrogen and fluorine react, so their equilibrium concentrations are different from the initial ones. ICE table?
 
Borek said:
Hydrogen and fluorine react, so their equilibrium concentrations are different from the initial ones. ICE table?

Thanks. How do you know when to use an ICE table in a question?
 
Whenever it is obvious that I, C and E are nicely defined.

Just don't use ICE table for buffer questions.
 
Borek said:
Whenever it is obvious that I, C and E are nicely defined.

Just don't use ICE table for buffer questions.

I tried an ICE table for a buffer solution once but it gives me the same answer as the Henderson-Hasselbalch equation anyways (which is quicker to plug in all the numbers.)
 
I never stated it is impossible to do buffer questions with ICE table, it just IMHO doesn't make sense.
 

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