What Was the Initial Quantity of Hydrogen Fluoride in the Reaction Jar?

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SUMMARY

The equilibrium constant (Keq) for the reaction 2 HF (g) <--> H2 (g) + F2 (g) at a given temperature is 4. Given that a 1-liter jar contains 0.045 moles of fluorine at equilibrium, the initial concentration of hydrogen fluoride (HF) was calculated using an ICE table. The calculations yielded two potential values for HF concentration: 0.1125 M and 0.0675 M. However, after considering significant figures, the final concentration of HF is determined to be 0.11 M, assuming the 1-liter measurement is exact.

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Homework Statement



Keq at a given temperature is 4

2 HF (g) <--> H2 (g) + F2 (g)

A 1 Litre jar contains 0.045 moles of fluorine at equilibrium. What was the initial quantity of hydrogen fluoride in the reaction jar?


2. The attempt at a solution

I set the initial concentration of hydrogen fluoride as x, and filled in the attached ICE table.

Afterwards:

4 = (0.045)(0.045) / (x-0.09)^2

x = 0.1125 and 0.0675

Therefore, the final answer is 0.1125 M
 

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  • ICE Table.png
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Work looks good. Watch your sig figs. 0.090 moles of HF gas disappears, not 0.09 moles. Final answer should also be limited to 2 significant figures. So the final answer is not 0.1125 M but rather 0.11 M. This is assuming that the 1 Liter measurement is an exact measurement (i.e. it doesn't just have one sig fig but is excluded from sig fig considerations in that it is an exact number).
 
Your answer is better than the question itself. It never said you started with HF only. Not that it can be solved without this assumption.
 

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