# ICE chart, Equilibrium question

## Homework Statement

What is the value of Kc for the reaction H2(g) + F2(g) <=> 2HF(g) given that when 0.010 mol H2 and 0.050 mol F2 are added to a 1.00 L container, 0.0125 mol HF is present at equilibrium.

## The Attempt at a Solution

I'm confused about how to set up the ICE chart in this scenario. We have

H2(g) + F2(g) <=> 2HF(g)

.01....... (.05) ....... 0
-x ......-x ........... 2x
.01-x.....(.05-x) ..... (.0125)

2x = .0125, x = .00625,

[.0125] ^2 / [.01 - .00625] [ .05-.00625] = 9.3 x 10 ^-6

Which is the incorrect answer, 9.51 ^-1 is right but I'm not sure how to get there. Any help would be appreciated.

Last edited:

## Answers and Replies

Borek
Mentor
0.1 or 0.01?

0.1 or 0.01?

Oops, I'm sorry it's .01, .05, Any ideas :D?

Borek
Mentor
Check your math. Formula you derived looks OK to me and its value is not 9.3x10-6. Or at least that's not what I got just by keying it into a calculator.

Check your math. Formula you derived looks OK to me and its value is not 9.3x10-6. Or at least that's not what I got just by keying it into a calculator.

Ugh...That feeling when you stress out over a question just to type in the right answer 45 minutes later. Thanks you sir!