- #1
1calculus1
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Consider the following equilibrium:
CO(g) + 2H2(g) <-> CH3OH(g)
Some CO, H2 and CH3OH were placed in a 1.0L container. When equilibrium
was established, the [CO] had increased. Which of the following is true?
A. Trial Keq > Keq so reaction shifted left to reach equilibrium.
B. Trial Keq < Keq so reaction shifted left to reach equilibrium.
C. Trial Keq > Keq so reaction shifted right to reach equilibrium.
D. Trial Keq < Keq so reaction shifted right to reach equilibrium.So, my answer is letter "b". However, I had found out from the provincial answer that this is wrong. Now, I'm boggled because keq = [products]/[reactants] therefore, IF the [CO] has increased which is a reactant, the products would be smaller than the reactant and therefore resulting a smaller keq than the original keq.
So, am I wrong? Or is the provincial answer wrong?
(The answer from the provincial is letter "a")
CO(g) + 2H2(g) <-> CH3OH(g)
Some CO, H2 and CH3OH were placed in a 1.0L container. When equilibrium
was established, the [CO] had increased. Which of the following is true?
A. Trial Keq > Keq so reaction shifted left to reach equilibrium.
B. Trial Keq < Keq so reaction shifted left to reach equilibrium.
C. Trial Keq > Keq so reaction shifted right to reach equilibrium.
D. Trial Keq < Keq so reaction shifted right to reach equilibrium.So, my answer is letter "b". However, I had found out from the provincial answer that this is wrong. Now, I'm boggled because keq = [products]/[reactants] therefore, IF the [CO] has increased which is a reactant, the products would be smaller than the reactant and therefore resulting a smaller keq than the original keq.
So, am I wrong? Or is the provincial answer wrong?
(The answer from the provincial is letter "a")