Chemistry: dissolving aluminum metal in hydrochloric acid

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Discussion Overview

The discussion revolves around a homework problem involving the dissolution of aluminum metal in hydrochloric acid, focusing on stoichiometry and the necessary calculations to determine the volume of HCl required. The scope includes mathematical reasoning and conceptual clarification related to chemical reactions and stoichiometric conversions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • The original poster (O.P.) presents the balanced chemical equation for the reaction between aluminum and hydrochloric acid and expresses uncertainty about the next steps in the stoichiometric calculations.
  • Some participants suggest converting moles to mass or mass to moles as part of the stoichiometric process, indicating differing preferences for approaching the problem.
  • One participant outlines a stepwise method to find the volume of HCl, including finding moles of aluminum, determining moles of HCl using the reaction ratio, and calculating the volume based on concentration.
  • A participant raises a question about the potential need for a catalyst, specifically copper chloride, to enhance the reaction, while another participant notes that this may not be relevant for the O.P.'s entry-level context.

Areas of Agreement / Disagreement

Participants generally agree on the need to apply stoichiometry to solve the problem, but there are differing opinions on the best approach to take. The relevance of catalysts in this context remains contested, with some participants suggesting it may not be appropriate for the O.P.'s level of study.

Contextual Notes

There is an assumption that participants are familiar with stoichiometric calculations and the properties of the reactants involved. The discussion does not resolve the question of catalyst necessity, leaving it open to interpretation based on the context of the problem.

Madelin Pierce
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Homework Statement


Aluminum metal dissolves in hydrochloric acid. What volume, in mL, of 1.58 M HCl is needed to completely dissolve 3.200 g of aluminum?(Hint: write the single-replacement reaction first)

Homework Equations


V[1]M[1]=V[2]M[2]

The Attempt at a Solution


I got the single-replacement reaction:
2Al(s) + 6HCl(aq) = 2AlCl[3](aq) + 3H[2](g)
But from there, I'm not really sure what to do. I think stoichiometry's involved, but I'm not sure how to use it.
 
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If you have
Madelin Pierce said:
2Al(s) + 6HCl(aq) = 2AlCl[3](aq) + 3H[2](g)
you have the stoechiometry ! My guess is that it's time to convert mol(ecul)es to mass :rolleyes:
 
BvU said:
My guess is that it's time to convert mol(ecul)es to mass

I would rather convert mass to moles :wink:
 
Sure, and perhaps you can explain to the audience why this is a better idea (generally or in this sspecific case) ?
 
Stepwise path to find the volume of HCl,

Find moles of Aluminum (need formula weight of Aluminum)
Find moles of HCl (use ratio according to reaction)
Find volume of HCl solution of 1.58 M (concentration computation)
 
Am I correct in remembering that you may need to add a near-catalytic amount of copper chloride to accelerate breakdown of surface passivation ?

Or was this just for 'Activated Zinc' ??
 
Nik_2213 said:
Am I correct in remembering that you may need to add a near-catalytic amount of copper chloride to accelerate breakdown of surface passivation ?

Or was this just for 'Activated Zinc' ??
Not in range. O.P. wants entry level course help, like for a beginning course. I am not saying that some kind of catalyst is not needed, but just that the idea is not in the range of the person's study.
 

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