Chemistry Problem: Obtaining Ag(2)S from 19.00g Ag, @.80 H(2)S & 1.600g O(2)

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SUMMARY

The discussion centers on calculating the amount of silver sulfide (Ag2S) produced from a reaction involving 19.00g of silver (Ag), 0.80g of hydrogen sulfide (H2S), and 1.600g of oxygen (O2). The balanced chemical equation is 4Ag + 2H2S + O2 → 2Ag2S + 2H2O. Participants emphasize the importance of identifying the limiting reagent to determine the maximum yield of Ag2S and the remaining quantities of non-limiting reactants.

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  • Understanding of stoichiometry in chemical reactions
  • Knowledge of limiting and excess reactants
  • Familiarity with molar mass calculations
  • Basic principles of chemical equations and balancing
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  • Calculate the molar mass of silver (Ag), hydrogen sulfide (H2S), and oxygen (O2)
  • Learn how to determine the limiting reagent in a chemical reaction
  • Practice stoichiometric calculations using different chemical equations
  • Explore the concept of yield and how to calculate theoretical yield from reactions
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Chemistry students, educators, and anyone involved in chemical reaction calculations or stoichiometry. This discussion is particularly beneficial for those tackling limiting reagent problems in chemistry coursework.

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Homework Statement



silver tarnishes in the presence of hydrogen sulfide (rotten egg odor), also found in Chinese dry wall and oxygen because of the reaction:

4Ag + 2H(2)S + O(2) --> 2Ag(2)S + 2H(2)O

How many grams of Ag(2)S could be obtained from a mixture of 19.00g Ag, @.80 H(2)S and 1.600g O(2) and how many grams of the non-limiting reactants are left.

Homework Equations


I am completely lost and have no idea how to even start this equation, I need some hekp thanks


The Attempt at a Solution


Not sure
 
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This is a limiting reagent question, just there are three reagents to take into account.

Ignore everything else for now - how many grams of H2S will react with 19.00g of Ag? Do you have that much H2S?

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