[Chemistry] Chemical Reaction, limiting reactants and result stoichiometry

[bnosam]

Homework Statement

609.5 grams of vanadium (II) oxide, VO, and 832 grams of iron(III) oxide, Fe₂O₃, react according to the equation, which substance(s) and how many grams of each would be in the tube after the reaction completes? 3 points

Homework Equations

Equation:

2 VO + 3 Fe₂O₃ -> 6 FeO + V₂O₅

3.

1 mol VO = 66.94 g
1 mol Fe₂O₃ = 159.70 g

$\frac{609.5 g VO}{66.94 g/mol VO} = 9.11 mol VO$

$\frac{832 Fe_{2}O_{3}}{159.7 g/mol Fe_{2}O_{3}} = 5.21 molFe_{2}O_{3}$

The Attempt at a Solution

$\frac{9.11 mol VO * 3 mol Fe_{2}O_{3}}{2 mol VO} = 13.6 mol Fe_{2}O_{3}$

$\frac{5.21 mol Fe_{2}O_{3} * 2 mol VO}{3 mol Fe_{2}O_{3}} = 3.47 mol VO$So the limiting reactant would be $Fe_{2}O_{3}$, right?

I'm not quite sure where to go after this, any pointers in the right direction?

Thanks :)

 

[AGNuke]

Consume all the Limiting reagent to form products. Find the amount of excess reagent used with LR, find the amount of products. Balanced Stoichiometric equation helps.