Choosing a committee from a class

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SUMMARY

The correct method to determine the number of ways to choose a 5-member committee from a class of 34 students is to use the combinations formula, specifically 34!/(5!*(34-5)!). This results in 278,256 unique combinations. The initial calculation using permutations, 34!/(34-5)!, yielding 33,390,720, is incorrect for this scenario as the order of selection does not matter in committee formation. Therefore, the combinations method is the appropriate approach.

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  • Understanding of factorial notation and calculations
  • Knowledge of combinations and permutations
  • Familiarity with the formula for combinations: n!/(r!(n-r)!)
  • Basic algebra skills for simplifying factorial expressions
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  • Practice solving problems using the combinations formula
  • Explore advanced combinatorial concepts such as binomial coefficients
  • Learn about real-world applications of combinations in statistics and probability
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Students in mathematics, educators teaching combinatorial concepts, and anyone preparing for exams involving combinatorial problems.

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Homework Statement


How many ways can a 5-member committee be chosen from a class with34 students?


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The Attempt at a Solution



Using the formula from the book, I did 34! / (34-5)! and I got 33,390,720.

This gives me the same answer as doing 34*33*32*31*30, but that's the Permutations method. I thought in Permutations the order mattered, and in combinations they did not. But the order doesn't matter here. But the Combinations method of 34!/(5!*(34-5)!) gives me 278256 ways. Which way is right??!
 
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The second way. The permutations don't matter here. The committee will be the same regardless of the order the members are chosen in. Hence, it will be 34!/(5!*(34-5)!).
 

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