Choosing a committee from a class

1. Aug 27, 2007

gabby989062

1. The problem statement, all variables and given/known data
How many ways can a 5-member committee be chosen from a class with34 students?

2. Relevant equations

3. The attempt at a solution

Using the formula from the book, I did 34! / (34-5)! and I got 33,390,720.

This gives me the same answer as doing 34*33*32*31*30, but that's the Permutations method. I thought in Permutations the order mattered, and in combinations they did not. But the order doesn't matter here. But the Combinations method of 34!/(5!*(34-5)!) gives me 278256 ways. Which way is right??!
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Aug 27, 2007

chaoseverlasting

The second way. The permutations dont matter here. The committee will be the same regardless of the order the members are chosen in. Hence, it will be 34!/(5!*(34-5)!).