MHB Choosing the Fastest 3 Horses from 25 - No Stopwatch Needed

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To determine the fastest three horses out of 25 without a stopwatch, participants suggest conducting five initial races with five horses each, totaling five races. The winners of these races can then be identified for further evaluation. The discussion emphasizes the need for a systematic approach to narrow down the fastest horses based on race outcomes. Participants are encouraged to think critically about the minimum number of races required to achieve the goal. The conversation remains focused on strategizing the selection process without introducing new threads for solutions.
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you have 25 horses and you have to pick fastest 3 out of the 25. In each race
only 5 horses can run at the same time as there are only 5 tracks. what is the
minimum number of races to pick the 3 horses without using a stopwatch.
 
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No answer yet so I provide a hint.

of course all 25 horses to run . So there will be 5 races of 5 horses each.
now the hint question

which horses run in 6th race and beyond
 
My solution

you make the horses into 5 groups of 5 horses each say A,B,C,D,E . have 5 races. then pick the winner of the 5 races and have a race that is race number 6.
Now pick the 3 winners out of the 5. Say the winner is from group A, the 2nd ranked is from Group B and 3rd one is from group C.
now let the 1st 3 positions in group A be A1,A2,A3. in group B be B1,B2,B3. and in group C be C1,C2, C3.
A1 is the 1st. B3 cannot be in top 3 beacuse A1, B1, B2 are faster.
So B3 is ruled out.
C2 and C3 cannot be in top 3 as A1,B1,C1 are faster. So have a race among A2,A3,B1,B2,C1 and choose the 2 fastest. the ranks shall be 2nd and 3rd.
So we need 7 races.
 
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kaliprasad said:
you have 25 horses and you have to pick fastest 3 out of the 25. In each race
only 5 horses can run at the same time as there are only 5 tracks. what is the
minimum number of races to pick the 3 horses without using a stopwatch.
now I am interested in the following question:
what is the minimax number of races to ensure the 3 horses can be chosen without using a stopwatch ?
 
Albert said:
now I am interested in the following question:
what is the minimax number of races to ensure the 3 horses can be chosen without using a stopwatch ?

IMHO new question should start on a new thread
 
kaliprasad said:
My solution

you make the horses into 5 groups of 5 horses each say A,B,C,D,E . have 5 races. then pick the winner of the 5 races and have a race that is race number 6.
Now pick the 3 winners out of the 5. Say the winner is from group A, the 2nd ranked is from Group B and 3rd one is from group C.
now let the 1st 3 positions in group A be A1,A2,A3. in group B be B1,B2,B3. and in group C be C1,C2, C3.
A1 is the 1st. B3 cannot be in top 3 beacuse A1, B1, B2 are faster.
So B3 is ruled out.
C2 and C3 cannot be in top 3 as A1,B1,C1 are faster. So have a race among A2,A3,B1,B2,C1 and choose the 2 fastest. the ranks shall be 2nd and 3rd.
So we need 7 races.
very good, but there is a flaut, if actural speeds of B3,C2,and C3 are faster than the speeds of A2 and A3
but they did not have a chance for the last trophies competition ,this sounds strange !
 
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Albert said:
very good, but there is a flaut, if actural speeds of B3,C2,and C3 are faster than the speeds of A2 and A3
but they did not have a chance for the last trophies competition ,this sounds strange !

we are looking at 1st 3 candiddates c2 and c3 cannot come as A1,B1,C1 all 3 are faster than these.
B3 cannot come in top 3 as at least 3 candidates A1, B2, B1 are faster. Of course 5 fastest re not in race 7 but 2 fastest
and 3 others are in the race as A1 is fastest for sure.
 
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