Circuit Analysis with Two Batteries and an Ammeter

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Homework Help Overview

The discussion revolves around a circuit analysis problem involving two batteries and an ammeter, focusing on the current reading when a switch is closed. The subject area includes circuit theory and electrical principles.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the current using Ohm's law, questioning the impact of the second battery and additional resistors on the ammeter reading. Other participants raise questions about the voltage across the resistor and the factors influencing it. One suggestion involves applying the principle of superposition to analyze the circuit.

Discussion Status

The discussion is active, with participants exploring different interpretations of the circuit behavior. Some guidance has been offered regarding the properties of ideal voltage sources, but no consensus has been reached on the overall approach to the problem.

Contextual Notes

Participants are considering the implications of ideal versus real components in the circuit, including the assumption of no internal resistance in the batteries. There may be constraints related to the information provided in the problem statement.

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Homework Statement


http://imgur.com/6Cds4YF

What will the ammeter read when the switch is closed?

Homework Equations


V = IR

The Attempt at a Solution


I already calculated the emf of the battery one the left to be about 27 V.
It seems that the answer to the question is as simple as using V = IR where V is from the battery.
So I = V/R = 25/50 = 0.5 A.

I don't understand why the other battery to the left and the other resistors don't affect the current through the ammeter though. Wouldn't using the numbers for calculating the current, assume that the only item in the circuit is a 25 V battery and one 50 ohm resistor?
 
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What is the voltage across the 50 ohm resistor? What factors affect what that voltage is?
 
Use principle of superposition, one battery at a time.
 
If the battery has no internal resistance it behaves like an ideal voltage source. Think about the properties of an ideal voltage source.
 

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