Circular Motion and angular speed

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SUMMARY

The discussion centers on calculating the angular speed and the length of thread wound on a grinding wheel with a radius of 9.0 cm, moving at a linear speed of 6.0 m/s. The angular speed (ω) is determined using the formula ω = v/r, resulting in an angular speed of 66.67 radians per second. Additionally, in 3.0 seconds, the length of thread that can be wound on the wheel is calculated to be 18.0 meters, derived from the linear distance covered at the given speed.

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It is desired that the outer edge of a grinding wheel 9.0 cm in radius move at a rate of 6.0 m/s. Determine the angular speed of the wheel. What length of thread could be wound on the rim of the wheel in 3.0 sec when it is turning at this rate?

tell me if i started off right becuz i honestly don't have a clue here

first i did
[tex]\theta[/tex]= s/r
56.52/9.0 = 66.6cm
this got me the arclength
now i was thinking about dividing it by T which should be .0942s
 
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Isn't the outside point supposed to be moving at 6 m/s?

How many meters is 3 sec at 6 m/s?

As for ω isn't that just v/r in radians per sec?
 

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