Circular Motion and Gravitation of a star

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SUMMARY

The discussion centers on the gravitational dynamics of two equal-mass stars rotating around a midpoint, maintaining a distance of 8.0 x 1010 m with a revolution period of 12.6 years. The gravitational force equation, F = G*m1*m2/r2, was applied incorrectly by assuming the distance r was half of the actual distance between the stars. The correct mass of each star, calculated using the corrected distance, is approximately 9.6 x 1026 kg, resolving the discrepancy noted by the participant.

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Carpe Mori
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Homework Statement


Two equal-mass stars maintain a constant distance apart of 8.0 x10^10 m and rotate about a point midway between them at a rate of one revolution every 12.6 yr
(a) why don't the two stars crash into one another due to the gravitational force between them
(b) what must be the mass of the stars

Homework Equations



F = G*m1*m2/r^2
F(r) = ma(r)
a(r) = v^2/r
v = 2*pi*r/T

The Attempt at a Solution


part b i said m1 = m2 = m
F = ma(r)
F(12) = m*(2*pi*r/T)^2 / r
F(12) = G*m^2 / r^2

substitution and solving for m gave me

m = ((2*pi*r)^2 * r )/ (G*T^2)

substituting i got 2.4 *10^26 kg

answer in book is like 9.6*10^26 kg

can someone point out my error(s) to account for this discrepancy?
 
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anyone?
 
oh snaps i figured it out

if anyone cares...

my mistake was that in the equation for graviational attractive force (F = G*m1*m2/r^2) the r is actual distance between the two center of masses and my mistake was that i thought it was half of that distance (the radius)

so yeah...cheers?
 

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