- #1

NotKepler

- 15

- 0

## Homework Statement

What is the distance from the Earth's center to a point outside the Earth where the gravitational acceleration duo to Earth is 1/10 of its value at the Earth's surface?

## Homework Equations

F = Gm

_{1}m

_{2}/r

^{2}

F = m

_{1}(v

^{2}/r)

Mass of Earth = 5.98x10

^{24}

G = 6.67x10

^{-11}

## The Attempt at a Solution

From using the two equations stated above I got the equation: Gm

_{1}/r

^{2}= v

^{2}/r

Since I know that v^2/r is equal to 1/10 the Earth's surface gravity (9.8m/s^2) I got Gm

_{1}/r

^{2}= 0.98

Then I plugged everything in and got 20,152,479.97 meters as an answer

Is my work correct?

Thank you,

-Tim