Circular motion-find the minimum speed

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To maintain a circular path, the minimum speed of the ball is determined by the gravitational force acting on it at the top of the circle. At this point, the tension in the string becomes zero, meaning the centripetal force required for circular motion is provided solely by gravity. The formula for minimum speed (v) can be derived from the equation v = √(g * r), where g is the acceleration due to gravity and r is the radius of the circle. For a 1.2m string, the minimum speed is approximately 3.43 m/s. Understanding these principles clarifies the relationship between speed, tension, and gravitational force in circular motion.
Shad94
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The question is:

A ball of a mass 4kg is attached to the end of a 1.2m long string and whirled around in a circle that describes a vertical plane..what is the minimum speed that the ball can be moving at and still maintain a circular path?

i try solve it by use T+mg=mv*2/r.But i can't find the tension...
 
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Shad94 said:
The question is:

A ball of a mass 4kg is attached to the end of a 1.2m long string and whirled around in a circle that describes a vertical plane..what is the minimum speed that the ball can be moving at and still maintain a circular path?

i try solve it by use T+mg=mv*2/r.But i can't find the tension...

You don't need to calculate the tension. What is the condition for the "minimum speed"?
Or what happens with T when v is less than that minimum?
 
Can you give me the answer...because i still don't understand it..
 
nasu said:
You don't need to calculate the tension. What is the condition for the "minimum speed"?
Or what happens with T when v is less than that minimum?

Can you give me the answer...because i still don't understand it..
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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