Vertical Circle (Circular Motion)

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Homework Help Overview

The problem involves a metal ball being swung in a vertical circle with a string of length 1.60m. The tension in the string at the bottom of the circle is stated to be 60.0N greater than at the top, and the task is to find the mass of the ball while considering the dynamics of circular motion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate the tensions at the top and bottom of the circle using an equation but expresses uncertainty about their reasoning. Some participants question the derivation of the equation used and seek clarification on the meaning of the terms involved. Others raise concerns about the implications of conservation of energy in the context of the problem, particularly regarding the constancy of speed.

Discussion Status

The discussion is exploring various interpretations of the problem setup, particularly regarding the forces acting on the ball and the implications for energy conservation. Participants are engaging in questioning assumptions and clarifying the problem's wording, but no consensus has been reached.

Contextual Notes

There are discussions about potential external forces affecting the system and the implications for conservation of energy, indicating that the problem may have unusual constraints or assumptions that need to be considered.

Mohammed S
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Homework Statement


You swing a 1.60m long string with a metal ball attached to its end in a vertical circle, such that the speed of the ball does not change but the rope is always taut. The tension in the string when the ball is at the bottom of the circle is 60.0N more than the tension when the ball is at the top. Find the mass of the ball.

Homework Equations


Fc=mv^2/r
ac=v^2/r
Equations that have to do with vertical circle

The Attempt at a Solution


I do not understand vertical circles but I tried doing the Tbottom=Ttop+6mg
I am unsure of the answer but I did 60+Ttop=Ttop+6mg
60=6mg
10=mg
m=1.02 kg
but I think its wrong
 
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Mohammed S said:
Tbottom=Ttop+6mg
Can you explain how you arrived at this equation. In particular, what does the 6mg denote?
 
Draw a diagram showing the forces on the ball at the top and at the bottom of the circle.
 
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Mohammed S said:
You swing a 1.60m long string with a metal ball attached to its end in a vertical circle, such that the speed of the ball does not change but the rope is always taut.
Question: How can the speed not change? What happened to conservation of energy? Is this the exact wording of the original problem?
 
Are there external forces acting on the system? If they are, there is no conservation of energy.
 
gneill said:
Question: How can the speed not change? What happened to conservation of energy? Is this the exact wording of the original problem?

There would have to be some tangential forces being applied and modulated just so. However there is no law against it, and, assuming these extra forces are truly purely tangential, they don’t prevent you from answering the question. So it’s an unusual construct, but it makes answering the question very easy.
 

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