Circular Motion of a Car: Finding Friction Coefficient

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Homework Help Overview

The discussion revolves around the circular motion of a car on a flat curve, specifically focusing on determining the static friction coefficient required for the car to navigate a turn at a speed of 60 km/h. Participants reference Newton's second law and centripetal force equations in their attempts to analyze the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between frictional force and centripetal force, with some attempting to derive equations involving mass, radius, and gravitational acceleration. Questions arise regarding unit conversions and the setup of the problem, as well as the clarity of the initial attempts.

Discussion Status

The discussion is ongoing, with various participants offering insights and attempting to clarify the problem. Some have provided partial guidance on the relationships between forces, while others express confusion and seek further assistance. There is no explicit consensus on the approach yet.

Contextual Notes

Participants note the importance of converting units and understanding the equations involved, while some express uncertainty about their initial calculations and the overall setup of the problem.

vitesse86
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Homework Statement



I have a general question about circular motion of a car on a flat curve.
What must the static friction koefficient be if the car can make the swing by 60km/h?

Thank you,

Homework Equations



- We have to follow Newtons 2nd law.

- Fcentripetal = m*(v^2/r)

known stats:
r= 150m
v= 16,67m/s
g= 9,81



The Attempt at a Solution



mg = v2/r /g

m= v2/r*g

m= ((16,67*16,67)/(150*9,81))

m= 0.189


Need probably help here, not sure if I did do the equations right.
 
Last edited:
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Surely they must also have given you the radius of the track?

Have you any idea how to start the problem?
 
H_man said:
Surely they must also have given you the radius of the track?

Have you any idea how to start the problem?

Hi,

the radius is 150m.

Thanks,
 
Can someone help me please, need help as soon as possible.



, thanks!
 
vitesse86 said:

Homework Statement



I have a general question about circular motion of a car on a flat curve.
What must the static friction koefficient be if the car can make the swing by 60km/h?

Thank you,

Homework Equations





The Attempt at a Solution



So, frictional force equals to centripetal force, and also equals to that coefficient times normal force.

Find centripetal, and thus that's the frictional force (it's keeping the car in that circle)
and then
Fn.coefficient = Centripetal force
mass cancels out..
and
so
g.coefficient = centripetal acc..

hoping this would help
 
Last edited:
harmeet_angel said:
So, frictional force equals to centripetal force, and also equals to that coefficient times normal force.

Find centripetal, and thus that's the frictional force (it's keeping the car in that circle)
and then
Fn.coefficient = Centripetal force
mass cancels out..
and
so
g.coefficient = centripetal acc..

hoping this would help


Hi,
thanks for the help.
But can't you help me a little closer, I am pretty new to this and I am also a newbee.

Thanks,
 
Centripetal = v^2/r
v=60 km/hr -- convert this is m/s
r=150 m

g.Answer = (v^2/r)
Answer = (v^2/r).g

sounds like a weird answer.. perhaps me wrong
 
harmeet_angel said:
Centripetal = v^2/r
v=60 km/hr -- convert this is m/s
r=150 m

g.Answer = (v^2/r)
Answer = (v^2/r).g

sounds like a weird answer.. perhaps me wrong

Can somebody help us here, please honestly!
 
harmeet_angel said:
g.Answer = (v^2/r)

Thats it, just make sure you convert units and then divide by g
 
  • #10
turdferguson said:
Thats it, just make sure you convert units and then divide by g

My english are abit bad, can you please write down for me how to do this?

f_on_car_1.gif

use this as a helping figure.
 
Last edited:
  • #11
hmm.. ite

so,
the answer for your question is = (v^2/(r.g))
v=16.67 m/s
r=150 m
g= 9.81

and so answer = 0.189
 
  • #12
harmeet_angel said:
hmm.. ite

so,
the answer for your question is =
v=16.67 m/s
r=150 m
g= 9.81

and so answer = 0.189

Can you show me the calculations how u did come
to (v^2/(r.g)) ?

Sorry I am a very newbee, and need everything in with a big fork



please help someone.:frown:
 
  • #13
vitesse86 said:
Can you show me the calculations how u did come
to (v^2/(r.g)) ?

Since this is a homework question, no one will calculate the answer for you. In fact, harmeet has given you lots of help, considering the fact that you have done nothing yet.

How about filling in numbers 2 and 3 in the homework posting template. What do you know? e.g. Do you know the equation to calculate centripetal force?
 
  • #14
cristo said:
Since this is a homework question, no one will calculate the answer for you. In fact, harmeet has given you lots of help, considering the fact that you have done nothing yet.

How about filling in numbers 2 and 3 in the homework posting template. What do you know? e.g. Do you know the equation to calculate centripetal force?

You are right.

There, i did filling in, and did an attempt.

Was it right or?


thanks for any help,
 

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