Circular motion of a subway train

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SUMMARY

The discussion focuses on calculating the radius of a turn for a subway train traveling at 67 km/h while rounding an unbanked curve. The correct radius, as confirmed by the book, is 132 meters. The solution involves applying Newton's second law and trigonometric relationships to derive the radius using the formula r = v^2 / (g tan 15 degrees). The initial calculation incorrectly yielded 475 meters, highlighting the importance of unit conversion from km/h to m/s.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Familiarity with trigonometric functions (sine, cosine, tangent)
  • Ability to convert units (km/h to m/s)
  • Knowledge of free-body diagrams in physics
NEXT STEPS
  • Learn about unit conversion techniques in physics, specifically km/h to m/s
  • Study the application of free-body diagrams in circular motion problems
  • Explore the effects of banking angles on the radius of curves in transportation
  • Investigate the role of friction in unbanked curves for vehicles
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to explain concepts related to forces and motion in real-world scenarios.

Cantworkit
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Homework Statement


A subway train rounds an unbanked curve at 67 km/h. An unused strap makes an angle of 15 degrees to the vertical. What is the radius of the turn. The book answer is 132 m.


Homework Equations


F = ma = mv^2/r


The Attempt at a Solution


A free-body diagram shows a normal force pointing up 75 degrees from the horizontal axis. An mg force points down along the y axis.

Along the x-axis N sin 15 degrees = mv^2/r.

r = mv^2/N sin 15 degrees.

Along the y-axis N = mg cos 15 degrees.

Substituting, r = mv^2/mg sin 15 degrees/cos 15 degrees = v^2 / g tan 15 degrees

r = (67)^2 km^2/ H^2 / 9.8 m/s^2 / 3600 s^2/ h^2 * 1000 m/km / .268 = 475 m
 
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Cantworkit said:
A free-body diagram shows a normal force pointing up 75 degrees from the horizontal axis. An mg force points down along the y axis.

Along the x-axis N sin 15 degrees = mv^2/r.

r = mv^2/N sin 15 degrees.
Good.

Along the y-axis N = mg cos 15 degrees.
You mean: N cos 15 degrees = mg

Substituting, r = mv^2/mg sin 15 degrees/cos 15 degrees = v^2 / g tan 15 degrees
Good.

r = (67)^2 km^2/ H^2 / 9.8 m/s^2 / 3600 s^2/ h^2 * 1000 m/km / .268 = 475 m
First convert 67 km/h to m/s.
 

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