Circular Motion (ratio of velocities)

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SUMMARY

In the discussion, participants analyze the problem of determining the ratio of velocities (vA/vB) for two planets orbiting a star, where planet A's orbit radius is four times that of planet B. The relevant equations include v = omega * r and the centripetal acceleration formula a(centripetal) = v^2/r. The solution reveals that the ratio of their speeds is 0.5, which can be derived using Kepler's third law of planetary motion.

PREREQUISITES
  • Understanding of circular motion concepts
  • Familiarity with angular velocity (omega)
  • Knowledge of centripetal acceleration
  • Basic grasp of Kepler's laws of planetary motion
NEXT STEPS
  • Study Kepler's third law of planetary motion in detail
  • Learn about angular velocity and its relationship to linear velocity
  • Explore the derivation of centripetal acceleration formulas
  • Investigate the implications of orbital radius on velocity in circular motion
USEFUL FOR

Students in physics, particularly those studying mechanics and orbital dynamics, as well as educators looking for examples of circular motion applications.

Qualenal
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Homework Statement



Two small planets are moving in circular orbits around the same star. If the radius of the orbit of planet A is 4 times the radius of the orbit of planet B, find the ratio of their speeds vA/vB.

Homework Equations



Not really sure but
v=omega*r
a(centripetal)=v^2/r
UCM T=2*pi*r/v

The Attempt at a Solution


I honestly have no idea how to do this problem. I know the answer is .5 I just want to know how to get there!
 
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Qualenal said:

Homework Statement



Two small planets are moving in circular orbits around the same star. If the radius of the orbit of planet A is 4 times the radius of the orbit of planet B, find the ratio of their speeds vA/vB.

Homework Equations



Not really sure but
v=omega*r
a(centripetal)=v^2/r
UCM T=2*pi*r/v

The Attempt at a Solution


I honestly have no idea how to do this problem. I know the answer is .5 I just want to know how to get there!

Have a look at Kepler's third law. It may give you a starting point.
 

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