Clairaut's theorem and smooth functions

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Clairaut's theorem states that mixed partial derivatives are equal if the function is sufficiently smooth. The discussion questions whether this theorem is a special case of a broader theorem regarding C^k functions, specifically when k=2. It also inquires about the relationship between the existence of derivatives in the Hessian matrix and the conclusions of Clairaut's theorem. A clarification is made that while the Hessian being well-defined indicates the existence of second partial derivatives, it does not guarantee their equality unless local continuity is established. The conversation emphasizes the distinction between generalization and corollary in mathematical terms.
Simfish
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Hello
So, my advanced calculus book (Folland) has this theorem...
If f is of class C^k on an open set S, then...

\partial i_1 \partial i_2 ... \partial i_k f = \partial j_1 \partial j_2 \partial j_k f on an open set S whenever the sequence {j_1 ,..., j_k} is a reordering of the sequence {i_1 ,..., i_k}, which defines a smooth function when k = \infty

So my question is, is Clairaut's Theorem a special case of this? (when k = 2?). Also, is the existence of derivatives in the nxn Hessian matrix logically equivalent to the conclusion of Clairaut's Theorem? Does this theorem even have a name? (I can't find it on Wikipedia or Mathworld anywhere).
 
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You can see Clairaut as a special case but if you look at the proof of the theorem you stated, I suspect that it begins by proving Clairaut and then shows how your thm is a direct generalization (corollary) of it.

For your second question, I'm not sure I understand what you're asking, but if the Hessian matrix is well defined, it only means that the second partial derivatives all exist. It does not say anything about their being equal when they are locally continuous.
 
generalization and corollary aren't the same thing, quasar.
 

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