RespectableCheese
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No, you second point is backwards.martinbn said:This is not their argument! Their argument is
1) every value that can be predicted with certainty should be in the theory, if the theory is complete
2) here is an example of something that can be predicted with certainty but is not in the theory
Therefore the theory is not complete.
"... [the theory] would contain these values; these would then be predictable. This not being the case, we are left with the alternatives stated."
This chain of reasoning is immediately preceded by:
"More generally, it is shown in quantum mechanics that, if the operators corresponding to two physical quantities, say A and B, do not commute, that is, if AB ≠ BA, then the precise knowledge of one of them precludes such a knowledge of the other. Furthermore, any attempt to determine the latter experimentally will alter the state of the system in such a way as to destroy the knowledge of the first."
(The values they are referring to in the first quoted segment are the eigenvalues of non-commuting observables).