Classifying Complex Matrices with Cubed Identity: What Does Similarity Mean?

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Discussion Overview

The discussion revolves around classifying 3 x 3 complex matrices A such that A³ = I, focusing on the concept of similarity in the context of linear algebra. Participants explore the implications of classifying matrices up to similarity, eigenvalues, and characteristic polynomials.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant expresses confusion regarding the phrase "classify up to similarity," suggesting it may relate to equivalence classes.
  • Another participant clarifies that the task involves finding a set of matrices such that none are similar to each other, and any other such matrix is similar to one in that set.
  • A hint is provided regarding the eigenvalues of A, prompting further exploration of their properties.
  • One participant proposes that if A³ = I, then the eigenvalues of A must be 1, leading to the characteristic polynomial (x-1)³.
  • Another participant counters that the eigenvalues must be cube roots of unity, indicating that there are complex numbers other than 1 that satisfy A³ = I.
  • There is a suggestion that the characteristic polynomial could be x³ - 1, which contrasts with the previous claim.
  • A question is raised about the possibility of composing matrices from characteristic polynomials, indicating a search for further understanding.

Areas of Agreement / Disagreement

Participants express differing views on the nature of eigenvalues and characteristic polynomials related to matrices satisfying A³ = I. There is no consensus on the implications of these properties or how to classify the matrices.

Contextual Notes

Participants have not fully resolved the implications of eigenvalues and characteristic polynomials in this context, leading to ongoing uncertainty about the classification of matrices.

CoachZ
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The question posed is "Classify up to similarity all 3 x 3 complex matrices A s.t. A^{3} = I. I think the biggest problem I'm having is understanding what exactly this is asking me to do. The part that says "Classify up to similarity" is really throwing me off, so if someone could tell me what that implies, it would be very helpful!

Maybe it deals with equivalence classes, or something like that?
 
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CoachZ said:
… The part that says "Classify up to similarity" is really throwing me off, so if someone could tell me what that implies, it would be very helpful!

Maybe it deals with equivalence classes, or something like that?

Hi CoachZ! :smile:

Yes, it's putting two matrices in the same equivalence class if they are similar.
 
It means, can you find a set of complex 3x3 matrices s.t. A^3 = I, such that none of them are similar to each other, and any other such 3x3 matrix is similar to one of the matrices in your set?

Hint: what can you say about eigenvalues of A?
 
hamster143 said:
It means, can you find a set of complex 3x3 matrices s.t. A^3 = I, such that none of them are similar to each other, and any other such 3x3 matrix is similar to one of the matrices in your set?

Hint: what can you say about eigenvalues of A?

I think that I'm a little confused, because if A^3 = I, then the eigenvalues for A would simply be the eigenvalues for I, which is just 1,1,1, since I is a diagonal matrix. Therefore, the characteristic polynomial of such A must be in the form (x-1)^3, right? Is there a way to compose matrices from characteristic polys?
 
CoachZ said:
I think that I'm a little confused, because if A^3 = I, then the eigenvalues for A would simply be the eigenvalues for I,

No, the eigenvalues must have cube equal to 1, but there are complex numbers other than 1 itself with that property...

Therefore, the characteristic polynomial of such A must be in the form (x-1)^3, right?

No, for example the characteristic polynomial could be x^3-1 .

Is there a way to compose matrices from characteristic polys?

One would assume the textbook would have such information before asking this question.
 

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